Deluxe Ski Jump Forum

Posted: **07 Dec 2020, 21:14**

Hello,
I know that only Z(X) and Y(X) profiles are avalible. But is there maybe some workaround to get profile that is a function Y(Z) or X(Z)?

Posted: **07 Dec 2020, 21:46**

You have to define all profiles as function of x.

profiles y(z) x(z)